Calculating Combat: What am I doing wrong?

A friend of mine insists that 5 tanks (he is using Great Combiner) (from Kiev) can take out 8 militia (in Russia Northwest) regularly.

5 tanks

Attack 5 * 9 = 45
HP = 5 * 7 = 35

total = 80

8 militia

Defense 8 * 4 = 32
HP = 8 * 7 = 56

total = 88

Why are the tanks (80 attack/hp) beating militia (88 defense/hp)?

Sth is wrong with your calculation you cant simply att+hp to determine the outcome of a battle

You can't combine two separate clauses. I suggest only looking at the attack. So 45 max. att. vs 32 max. def. (keeping in mind that the neutral might reinforce to 9, therefore include the possibility of 36 max. def.)

The key is to be at least +7 attack over the neutral defense. However, the higher the deviation, for instance 5 tanks against 8 militia is a deviation of 3, will up your chances of equally losing because of the difference in hp and critical hit. Therefore, luck is a factor.

Usually, as GC, 5 tanks will defeat 8 neutral militia, but always assume that the neutral will reinforce to 9, so always send an extra infantry or two to insure victory.

Calculation should be different. According to AW officials, the logic is:

"Unit's Attack and Defence represent the maximum amount of damage you deal to the opponent. Attack and defence are executed simultaneosly, so you're guaranteed to deal some damage in a battle. Each unit has Hit points - so damage is applied directly to Hit points, and if the unit runs out of them, it gets destroyed. The remaining damage is then transferred to the next unit."

So the calculation should be:

Att. of the attacking unit against the HP of defending unit and simultaneously Def. of the defending unit against HP of attacking unit. Plus a "luck and upgraded luck" factor called Crit.

So:

[HP (Def.) - ATT (Att.)] & [DEF (Def.) - HP (Att.)] & [CRIT (Att.) / CRIT (Def.)]

In your case the militia should win (if Crit. is not applied). Lets see:

Tank has: 9 ATT and 7 HP
Militia has: 4 DEF and 7 HP

1st round:

• HP (Def.) = 56 (8 militia)
  
• ATT (Att.) = 45 (5 tanks)
  
• Result: 56-45 = 11 (2 militias left for second round; 1 militia with 7 HP and 1 militia with 4 HP)

• HP (Att.) = 35 (5 tanks)
  
• DEF (Def.) = 32 (8 militia)
  
• Result: 35-32 = 3 (1 tank left for second round with 3 HP)

2nd Round:

• HP (Def.) = 11 (2 militia)
  
• ATT (Att.) = 9 (5 tanks)
  
• Result: 11-9 = 2 (1 militia left with 2 HP)

• HP (Att.) = 3 (1 tank)
  
• DEF (Def.) = 14 (2 militia)
  
• Result: 3-14 = 0 (no tank left)

Summary:
1 militia left and 0 tanks.


Again, this is without counting the CRIT of the battles. The CRIT can change the end result, transforming a loss into a win. To be sure, send an additional infantry into the battle... again, an additional infantry could in a "worst case scenario" be not sufficient! LOL

Please correct this post if I'm wrong on the logic... it's what I understood so far.

Cheers,
CD

I interpreted it a little differently. When going through step by step I thought it went:

Round1:

5 Tank : 35 HP - (4 Defense from Militia) -> 31 HP
8 Militia : 56 HP - (9 Attack from Tanks) -> 47 HP

Round2:

31 HP -> 27 HP
47 HP -> 38 HP

(tank/militia)
(27/38)

Round 3 and on:

23/29
19/20
15/11
11/2
7/x ... tanks win

I don't know how to simplify this? TopHats suggested just looking at the attack/defense, but how can we evaluate IF hit point bonus in combat?

You are absolutely right; it has to go one by one... (in some cases even 3 tanks survive the combat)!

Doing some empirical research (engaging 5 tank vs 8 militia battles using GC; 100 battles), the results were:

• Tank 0 x 1 Militia: 5%
  
• Tank 1 x 0 Militia: 28%
  
• Tank 2 x 0 Militia: 42%
  
• Tank 3 x 0 Militia: 25%

Cheers,
CD

Γραμμένο από Columna Durruti, 17.04.2013 at 10:37

Doing some empirical research (engaging 5 tank vs 8 militia battles using GC; 100 battles), the results were:

• Tank 0 x 1 Militia: 5%
  
• Tank 1 x 0 Militia: 28%
  
• Tank 2 x 0 Militia: 42%
  
• Tank 3 x 0 Militia: 25%

Cheers,
CD

Nice work! 95% of the time is pretty much all the time.